Since there is no condition for plus (+) sign, fix them in a row.
+ + + + + + +.
There are 6 places in between each plus and one before and one after these plus (+) signs.
$i.e.,$ there are 8 places for minus (-) and 4 (-) signs are there.
$\therefore$ these minus (-) signs can be placed in $^8C_4$ ways.
The required no. of arrangements = $^8C_4=70$