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The resistance of 10.5 solution of an electrolyte in a cell was found to be

The resistance of 10.5 solution of an electrolyte in a cell was found to be 45 calculate the molar conductance of the solution if the electrodes in the cell are 2.2 cm apart and have an area of 3.8cm

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A)
Solution :
$R= 45 \Omega$
$\therefore G= s$
$K_{cell}=\large\frac{1}{n}$
$\qquad= \large\frac{22\;cm}{3.8\;cm^2}$$=0.5789\;cm^{-1}$
$\qquad= 57.89 \;m^{-1}$
$k= 57.89 m^{-1} \times \large\frac{1}{45} S $$ =1.286 \;sm^{-1}$
$\qquad= 25.72 \times 10^{-4} \;sm^{-2}mol^{-1}$
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