Question

The resistance of 10.5 solution of an electrolyte in a cell was found to be 45 calculate the molar conductance of the solution if the electrodes in the cell are 2.2 cm apart and have an area of 3.8cm

Answer 1

Solution :

$R= 45 \Omega$

$\therefore G= s$

$K_{cell}=\large\frac{1}{n}$

$\qquad= \large\frac{22\;cm}{3.8\;cm^2}$$=0.5789\;cm^{-1}$

$\qquad= 57.89 \;m^{-1}$

$k= 57.89 m^{-1} \times \large\frac{1}{45} S $$ =1.286 \;sm^{-1}$

$\qquad= 25.72 \times 10^{-4} \;sm^{-2}mol^{-1}$