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Home  >>  JEEMAIN and NEET  >>  Physics  >>  Class11  >>  Gravitation

A spaceship is lanunched into a circular orbit close to the earth's surface. What additional velocity has now to be imparted to the space ship in the orbit to overcome the gravitational pull. (Radius of earth$= 6400 km,g=9.8 m/s^2$)

\[(a)\;\sqrt 2 gR \quad (b)\;\sqrt {2gR} \quad (c)\;\sqrt {gR} \quad (d)\;(\sqrt 2-1) \sqrt {gR}\]

1 Answer

Orbital speed of satallite
$V_0=\sqrt {gR}$
$v_e$= escape velocity $=\sqrt {2gR}$
Additional velocity required to escape
$v_e-v_0=\sqrt {2gR}-\sqrt {gR}$
$\qquad= (\sqrt 2 -1)\sqrt {gR}$
Hence d is the correct answer.

 

answered Aug 20, 2013 by meena.p
edited Feb 17, 2014 by meena.p
 

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