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Home  >>  JEEMAIN and NEET  >>  Physics  >>  Class11  >>  Gravitation

A light planet revolving around a very massive star in a circular orbit of radius R with a period of revolution T. If the gravitational force of attraction between the planet and star is proportional to $R^{\large\frac{-5}{2}}$ then $T^2$ is proportional to

\[(a)\;R^3 \quad (b)\;R^{\frac{7}{2}} \quad (c)\;R^{\frac{3}{2}} \quad (d)\;R^{\frac{9}{2}}\]

1 Answer

Gravitational force $ \alpha\;R ^{\large\frac{-5}{2}}$
Centripelal force $\alpha\; R^{\large\frac{-5}{2}}$
$m R w^2 \;\alpha\; R^{\large\frac{-5}{2}}$
$w^2 \;\alpha \; R^{\large\frac{-5}{2} -1}$
$w^2 \;\alpha \; R^{\large\frac{-7}{2}}$
$\large\bigg(\frac{2 \pi}{T}\bigg)^2 \alpha\; $$R^{\large\frac{-7}{2}}$
$T^2 \alpha\; R^{\large\frac{7}{2}}$
Hence b is the correct answer.

 

answered Aug 21, 2013 by meena.p
edited Feb 17, 2014 by meena.p
 

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