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The correct decreasing order of vapour phase dipole moments of $CH_3-x$ is as follows

\begin{array}{1 1}(a) CH_3-F > CH_3-Cl > CH_3-Br > CH_3I \\(b) CH_3I > CH_3-Br > CH_3-Cl > CH_3-F\\ (c) CH_3-Cl > CH_3-F > CH_3-Br > CH_3I\\( d) CH_3-Cl > CH_3 -Br > CH_3I > CH_3-F\end{array}

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1 Answer

Although electro negativity of halogens follows the order $F > Cl > Br > I$ the dipole moment of F is less than that of chlorine because of small size of F atom suffers repulsion than that of chlorine atom .
answered Aug 21, 2013 by sreemathi.v