Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
Home  >>  JEEMAIN and AIPMT  >>  Physics  >>  Class11  >>  Gravitation
0 votes

A satellite of mass $m_s$ revolving in a circular orbit of radius $r_s$ round the earth of mass M has a total energy E. Then its angular momentum will be

\[(a)\;(2Em_sr_s^2)^{1/2} \quad (b)\;(2Em_sr_s^2) \quad (c)\;(2Em_sr_s)^{1/2} \quad (d)\;2Em_sr_s \]
Can you answer this question?

1 Answer

0 votes
Velocity $V_s$ of the satellite is given by
$ \large\frac{GMm_s}{r_s^2}=\Large\frac{n_s v_s^2}{r_s}$
$v_s =\sqrt {\bigg(\large\frac{GM}{r_{\Large s}}\bigg)}$
$KE= \large\frac{1}{2} m_s v_s=\large\frac{1}{2}$$ m_s\bigg(\frac{GM}{n_{\Large s}}\bigg)$
$PE= \large\frac{-GMm_{\Large}s}{r_{\Large s}}$
$E$ Total energy $=KE+PE$-----(1)
$\qquad= \large\frac{-GMm_s}{2r_{\Large s}}$
Angular momentum
$L= m_sv_sr_s$
$\quad= m_s \bigg( \large\frac{GM}{r_{\Large s}}\bigg)^{1/2} $$r_{\large s}$
$\quad= (GMm_s^2 r_s)^{1/2}$
Substituting from (1)
$L=(2Em_sr_s^2)^{1/2} $
Hence a is the correct answer.


answered Aug 24, 2013 by meena.p
edited Feb 17, 2014 by meena.p

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, AIPMT Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App