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$g_{\large earth}= \large\frac{G\;M_{\Large earth}}{R^2 _{\Large earth}}$

$g_{\large mass}= \large\frac{G\;M_{\Large mass}}{R^2 _{\Large mass}}$

$ \large\frac{g_{\Large mass}}{g _{\Large earth}}= \large\frac{M_{\Large mass}}{M _{\Large earth}} $$ \times \large\frac{R^2_{\Large earth}}{R^2 _{\Large mass}}$

$\qquad= \large\frac{\Large\frac{1}{10}Me}{Me} \times \large\frac{(D_1/2)^2}{(D_2/2)^2}$

$g_{\large mar}= \large\frac{1}{10} \times \large\frac{12742}{6760} $$ \times 9.8$

$\qquad= 3.03 \;m/s^2$

Hence b is the correct answer.

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