Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
Home  >>  JEEMAIN and AIPMT  >>  Physics  >>  Class11  >>  Gravitation
0 votes

A mass M is split into two parts m and (M-m) which are then separated by a certain distance. What ratio of m/M maximise the gravitational force between the parts?

\[(a)\;\frac{2}{3} \quad (b)\;\frac{3}{4} \quad (c)\;\frac{1}{3} \quad (d)\;\frac{1}{2} \]

Can you answer this question?

1 Answer

0 votes
Let r be the direction between the parts
$F= \large\frac{Gm(M-m)}{r^2}$
$\qquad= \large\frac{G}{r^2} $$(mM-m^2)$
The force will be maximum
ie $\large\frac{d}{dm} \bigg[\large\frac{G}{r^2} $$(mM-m^2)\bigg]=0$
or $\large\frac{m}{M}=\large\frac{1}{2}$
Hence d is the correct answer.


answered Aug 23, 2013 by meena.p
edited Feb 17, 2014 by meena.p

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, AIPMT Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App