Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
Home  >>  JEEMAIN and AIPMT  >>  Physics  >>  Class11  >>  Gravitation
0 votes

Mean distance of mars from sun is 1.524 times the distance of earth from sun. The period of revolution of mars around the sun is

\[(a)\;2.88\;earth\; year \quad (b)\;1.88\;earth\; year \quad (c)\;3.88\;earth\;year \quad (d)\;4.88\;earth\;year \]
Can you answer this question?

1 Answer

0 votes
We know that
$T^2 \;\alpha \; r^3$
$=> T \; \alpha \; r^{3/2}$
$ \large\frac{T_{\Large mars}}{T_{\Large earth}}=\bigg(\Large\frac{r _{mars}}{r_{earth}}\bigg)^{3/2}$
$\qquad= (1.524)^{3/2}$
$\qquad= 1.88 $
$T_{\large earth}=1 year$
$\therefore T_{\large mars}= 1.88 \;earth \;years$
Hence b is the correct answer.
answered Aug 24, 2013 by meena.p
edited Jul 3, 2014 by lmohan717

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App