(9am to 6pm)

Ask Questions, Get Answers

Want help in doing your homework? We will solve it for you. Click to know more.
Home  >>  JEEMAIN and NEET  >>  Physics  >>  Class11  >>  Gravitation

Suppose the gravitational force varies inversely as the n-th power of distance. Then the time period of a planet in circular orbit of radius 'r' around the sun will be proportional to

\[(a)\;r^{\bigg(\Large\frac{n+1}{2}\bigg)} \quad (b)\;r^{\bigg(\Large\frac{n-1}{2}\bigg)} \quad (c)\;r^n \quad (d)\;r^{\bigg(\Large\frac{n-2}{2}\bigg)} \]

1 Answer

Need homework help? Click here.
$F \; \alpha \; \large\frac{1}{r^n}$
$F= \large\frac{K}{r^n}=\large\frac{mv^2}{v}$
$v=\sqrt {\large\frac{R}{m} \bigg(\frac{1}{r^{n-1}}\bigg)}$
Time period $=T=\large\frac{2 \pi r}{v}$
$\qquad = 2 \pi r \sqrt {\large\frac{m}{R} \normalsize r^{n-1}}$
$\qquad = 2 \pi r \sqrt {\large\frac{m}{R} \normalsize r^{n+1}}$
$T \; \alpha \; r^{\bigg(\Large\frac{n+1}{2}\bigg)} $
Hence a is the correct answer. 


answered Aug 24, 2013 by meena.p
edited Feb 17, 2014 by meena.p

Related questions