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Home  >>  JEEMAIN and AIPMT  >>  Physics  >>  Class11  >>  Gravitation
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Two bodies of masses m and 4m are placed at a distance r . The gravitational potential at a point on the line joining them where the gravitational field is zero, is

\[(a)\;zero \quad (b)\;\frac{-4GM}{r} \quad (c)\;\frac{-6GM}{r} \quad (d)\;\frac{-9GM}{r} \]

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Let the point be the position when the gravitational field is zero
the point P is at a distance $\large\frac{r}{3}$ from mass m and $\large\frac{2r}{3}$ from mass 4m
$V= \large\frac{-GM}{\Large\frac{r}{3}}-\frac{G(4m)}{\Large\frac{2r}{3}}$
$\quad= \large\frac{-9GM}{r}$
Hence d is the correct answer. 
answered Aug 29, 2013 by meena.p
edited Jul 3, 2014 by lmohan717

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