Email
Chat with tutor
logo

Ask Questions, Get Answers

X
 
Questions  >>  JEEMAIN and NEET  >>  Physics  >>  Class11  >>  Gravitation
Answer
Comment
Share
Q)

Two bodies of masses m and 4m are placed at a distance r . The gravitational potential at a point on the line joining them where the gravitational field is zero, is

\[(a)\;zero \quad (b)\;\frac{-4GM}{r} \quad (c)\;\frac{-6GM}{r} \quad (d)\;\frac{-9GM}{r} \]

1 Answer

Comment
A)
Let the point be the position when the gravitational field is zero
$\large\frac{Gm}{x^2}=\large\frac{G(4m)}{(r-x)^2}$
$\large\frac{1}{x}=\frac{2}{(r-x)}$
$r-x=2x$
$x=\large\frac{r}{3}$
the point P is at a distance $\large\frac{r}{3}$ from mass m and $\large\frac{2r}{3}$ from mass 4m
$V= \large\frac{-GM}{\Large\frac{r}{3}}-\frac{G(4m)}{\Large\frac{2r}{3}}$
$\quad= \large\frac{-9GM}{r}$
Hence d is the correct answer. 
Help Clay6 to be free
Clay6 needs your help to survive. We have roughly 7 lakh students visiting us monthly. We want to keep our services free and improve with prompt help and advanced solutions by adding more teachers and infrastructure.

A small donation from you will help us reach that goal faster. Talk to your parents, teachers and school and spread the word about clay6. You can pay online or send a cheque.

Thanks for your support.
Continue
Please choose your payment mode to continue
Home Ask Homework Questions
Your payment for is successful.
Continue
Clay6 tutors use Telegram* chat app to help students with their questions and doubts.
Do you have the Telegram chat app installed?
Already installed Install now
*Telegram is a chat app like WhatsApp / Facebook Messenger / Skype.
...