\[(a)\;5.0 \times 10^{-12}\;J \quad (b)\;2.25 \times 10^{-10}\;J \quad (c)\;4.0 \times 10^{-11}\;J \quad (d)\;6.0 \times 10^{-15}\;J \]

Want to ask us a question? Click here

Browse Questions

Ad |

0 votes

0 votes

Work done= Final gravitational potential -Initial gravitational potential

$\qquad=v_f -v_i =3\bigg[\bigg(\large\frac{-Gmm}{r_f}\bigg)-\bigg(\frac{-Gmm}{r_i}\bigg)\bigg]$

$ m= 0.1 \quad r_f=0.4\;m \quad r_i=0.2\; m$

Substituting these values we get

$W= 3\bigg[-Gmm \bigg(\large\frac{1}{.4}-\frac{1}{.2}\bigg)\bigg]$

$W= 5.0 \times 10^{-12}J$

Hence a is the correct answer.

Ask Question

Take Test

x

JEE MAIN, CBSE, AIPMT Mobile and Tablet App

The ultimate mobile app to help you crack your examinations

...