a) is a universal constant $=\large\frac{3 \pi}{G}$

b) is a universal constant $=\large\frac{3 \pi}{2G}$

c) is proportional to radius of earth R

d) is proportional to square of earth's radius $R^2$ where $G=$ universal gravitational constant

Want to ask us a question? Click here

Browse Questions

Ad |

0 votes

a) is a universal constant $=\large\frac{3 \pi}{G}$

b) is a universal constant $=\large\frac{3 \pi}{2G}$

c) is proportional to radius of earth R

d) is proportional to square of earth's radius $R^2$ where $G=$ universal gravitational constant

0 votes

Time period of satellite above the earth surface

$T^2=\large\frac{4 \pi ^2 R^3}{GM}$

$\qquad= \large\frac{3 \pi}{G\bigg[\Large\frac{M}{4/3 \pi R^3}\bigg]}$

$\qquad=\large\frac{3 \pi}{3 \rho}$

When $ \rho$=density of earth $=\large\frac{Mass\;of\;earth}{volume\;of\;earth}$

$\qquad= \large\frac{M}{\Large\frac{4}{3} \pi R^3}$

$\therefore \rho T^2=\large\frac{3 \pi}{G}$$=$ constant

Hence a is the correct answer.

Ask Question

Take Test

x

JEE MAIN, CBSE, AIPMT Mobile and Tablet App

The ultimate mobile app to help you crack your examinations

...