Email
Chat with tutor
logo

Ask Questions, Get Answers

X
 
Questions  >>  JEEMAIN and NEET  >>  Physics  >>  Class11  >>  Gravitation
Answer
Comment
Share
Q)

If a planet orbiting the sun in a circular orbit suddenly stops, it will fall onto the sun in a time n(T) where T is the period of planets revolution , then n is

\[(a)\;\sqrt 8 \quad (b)\;\frac{\sqrt 2}{8} \quad (c)\; \sqrt 2 \quad (d)\;\sqrt 6 \]

1 Answer

Comment
A)
Let $r$ be the radius of the orbot of the planet around the sun .
Let time taken to reach the sun be $'t'$ .
Time taken for the planet to revolve around the sun of radius $r=T$
We consider the planet to reach the sun is an elliptical path with time period $2t'=T'$
By Kepler's law
$\large\frac{T'}{T} =\bigg( \large\frac{r'}{r}\bigg)^{3/2}$
$r'= \large\frac{1}{2} $$r$
$T'= T\bigg(\large\frac{1}{2}\bigg)^{3/2}$
$t'= T\bigg(\large\frac{1}{2}\bigg)^{3/2}$$ \times \large\frac{1}{2}$
$t'=\large\frac{\sqrt 2}{8}$$T$
Hence b is the correct answer.

 

Help Clay6 to be free
Clay6 needs your help to survive. We have roughly 7 lakh students visiting us monthly. We want to keep our services free and improve with prompt help and advanced solutions by adding more teachers and infrastructure.

A small donation from you will help us reach that goal faster. Talk to your parents, teachers and school and spread the word about clay6. You can pay online or send a cheque.

Thanks for your support.
Continue
Please choose your payment mode to continue
Home Ask Homework Questions
Your payment for is successful.
Continue
Clay6 tutors use Telegram* chat app to help students with their questions and doubts.
Do you have the Telegram chat app installed?
Already installed Install now
*Telegram is a chat app like WhatsApp / Facebook Messenger / Skype.
...