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The solution of the differential equation $\frac{dy}{dx}=\frac{x+y}{x}$ satisfying the condition y (1) = 1 is


( A ) y = x ln x + x
( B ) $y = xe^{(x-1)}$
( C ) $y = x \;ln\;x + x^2$
( D ) y = ln x + x

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