# In Cannizzaro reaction given below <br> $2 Ph \; CHO \xrightarrow{\overset{(-)}{: OH}} Ph \; CH_2OH + PhC\overset{..}{O}_2^{(-)}$ the slowest step is :
( A ) the deprotonation of $Ph \; CH_2OH$
( D ) the attack of : $\overset{(-)}{OH}$ at the carboxyl group