Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
0 votes

Ten persons are to speak in a meeting. The no. of ways in which this can be arranged if A wants to speak before B and B wants to speak before C, is ?

Can you answer this question?

1 Answer

0 votes
  • No. of arrangement of n different things out of which 'm' are of one category = $\large\frac{n!}{m!}$
The no. of arrangement of 10 speakers without any condition = $(10)!$
A,B, C can speak any order = $3!$ ways.
But A,B,C has a fixed arrangement.
$\therefore$ The required arrangement = $\large\frac{(10)!}{6}$
answered Aug 27, 2013 by rvidyagovindarajan_1

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, AIPMT Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App