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Let the line $\frac{x-2}{3} = \frac{y-1}{-5} = \frac{z+2}{2}$ lies in the plane $x+3y -\alpha z + \beta = 0$. Then $(\alpha, \beta)$ equals


( A ) (6, -17)
( B ) (-5, 15)
( C ) (-6, 7)
( D ) (5, -15)

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