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One ticket is selected at random from 50 tickets numbered $00, 01, 02, .....49$. Then the probability that the sum of the digits on the selected ticket is 8, given that the product of these digits is zero, equals


( A ) $\frac{1}{50}$
( B ) $\frac{1}{7}$
( C ) $\frac{5}{14}$
( D ) $\frac{1}{14}$

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