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Let $f(x) = x|x| $ and $g(x) = \sin x$ <br> Statement -1 : gof is differentiable at $x=0$ and its derivative is continuous at the point. <br> Statement -2 : gof is twice differentiable at $x=0$


( A ) Statement-1 is true, Statement-2 is false
( B ) Statement-1 is true, Statement 2 is true; Statement-2 is a correct explanation for Statement-1
( C ) Statement-1 is false, Statement-2 is true
( D ) Statement-1 is true, Statement 2 is true; Statement-2 is not a correct explanation for Statement-1

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