$\begin{array}{1 1} 5 \\ 6 \\ 7 \\ 8 \end{array}$

Want to ask us a question? Click here

Browse Questions

Ad |

0 votes

0 votes

- $^nC_0+^nC_1+^nC_2+.................^nC_{n-2}+^nC_{n-1}+^nC_n=2^n$

Let the no. of candidates = $n$

$\therefore$ The no. to be elected= $n-2$

A man can vote for these candidates in

$^nC_1+^nC_2+^nC_3+..........^nC_{n-2}$ ways = $ 56 $(given)

$\Rightarrow\: 2^n-^nC_0-^nC_{n-1}-^nC_n=56$

$\Rightarrow\:2^n-1-n-1=56$

$\Rightarrow\:2^n=58+n$

$\Rightarrow\:n=6$

Ask Question

Take Test

x

JEE MAIN, CBSE, NEET Mobile and Tablet App

The ultimate mobile app to help you crack your examinations

...