logo

Ask Questions, Get Answers

 
X
 Search
Want to ask us a question? Click here
Browse Questions
Ad
Home  >>  JEEMAIN and AIPMT  >>  Physics  >>  Class11  >>  Gravitation
0 votes

The radius of planet is R. A satellite revolves around it in a circular orbit of radius r with angular speed 'w'. The acceleration due to gravity on the planet's surface will be

\[(a)\;\frac{r^3w}{R} \quad (b)\;\frac{r^3w^2}{R^2} \quad (c)\;\frac{r^2w^3}{R^2} \quad (d)\;\frac{r^2w^2}{R} \]
Can you answer this question?
 
 

1 Answer

0 votes
Let M be mass of planet and m mass of satellite
$mrw^2=\large\frac{GMm}{r^2}$
$GM=r^3w^2$
But $ g= \large\frac{GM}{R^2}$
$\therefore g= \large\frac{r^3w^2}{R^2}$
Hence d is the correct answer. 

 

answered Aug 29, 2013 by meena.p
edited Feb 18, 2014 by meena.p
 

Related questions

Ask Question
student study plans
x
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App
...