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Home  >>  JEEMAIN and AIPMT  >>  Physics  >>  Class11  >>  Gravitation
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A sphere of mass M and radius $R_2$ has a concentric cavity of radius $R_1$ as shown. The force F exerted by the sphere on a particle of mass m located at a distance r from the center of sphere varies as $(0 < r < \alpha)$

Options are:

$\begin{array}{1 1} a \\ b \\ c \\ d \end{array}$

Can you answer this question?
 
 

1 Answer

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The whole space is divided into 3 regions
1) $0 < r< R_1 \qquad F(r)=0$
2) $R_2 < r< R_2 \qquad F(r)=\large\frac{4}{3} $$\pi G\rho m \bigg( r - \large\frac{R_1^3}{r^2}\bigg)$
3) $R_2 < r< \infty \qquad F(r)=\large\frac{4}{3} $$\pi G\rho m \bigg( \large\frac{R_2^3-R_1^3}{r}\bigg)$
In region 1 - $F=0$
In region 2 - $F$ increase gradually
In region 3 - $F$ decrease gradually
Hence c is the correct answer.

 

answered Aug 30, 2013 by meena.p
edited Feb 18, 2014 by meena.p
 

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