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Permutations and Combinations
There are Five balls of different colour and 3 boxes of different size. The balls are to be placed in the boxes so that no box is empty. In how many ways this can be done?
jeemain
math
class11
ch7
permutations-and-combinations
combinations
medium
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asked
Aug 31, 2013
by
rvidyagovindarajan_1
edited
Aug 5, 2014
by
sharmaaparna1
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1 Answer
Balls in the boxes can be (2,2,1),(1,2,2),(2,1,2) ways
$=3.(^5C_2.^3C_2.^1C_1)=90\:ways$
or
$(1,1,3),(1,3,1),(3,1,1) $
$=3.(^5C_1.^4C_1.^3C_3)=60\:ways$
$\therefore$ The required no. of arrangements = $90+60=150$
answered
Aug 31, 2013
by
rvidyagovindarajan_1
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