$\begin{array}{1 1} 35 \\ 252 \\ ^{16}C_4 \\ 12 \end{array}$

Since each student should get atleast 3 prizes, 12 prizes are distributed

(by giving 3 prizes each)

Remaining 4 prizes are to be distributed among the 4 students.

Here any two students are selected and one is given 3 prizes

and other 1 prize = $^4C_2.2=12 \:ways$

Here any two students are selected and 2 prizes are given to each.

$^4C_2=6\:ways$

Here any 3 stdents are selected and given 1 prize to any 2 and 2

prizes to the third one.

This can be done in $^4C_3\times 3=12\:ways$

Here each get one prize = 1 way

$\therefore$ The required no. of ways $=4+12+6+12+1=35 \:ways$

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