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# How many 6 digit numbers can be formed using the digits 0,1,3,5,7,9 that are divisible by 5? (digits should not be repeated)

$\begin{array}{1 1} 216 \\ 240 \\ 720 \\ 96 \end{array}$

Fixing 0 in the last place we can have $5!$ =120 numbers.
$i.e.,$ Fixing 0 at the first place and 5 at the last place,
we can have $4!=24$ numbers which are 5 digit numbers.
$\therefore$ The required 6 digit numbers = $120+120-24=216$