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Let $f : (-1, 1) \to R$ be a differentiable function with $f(0) = -1$ and $f'(0)=1$. Let $g(x) = [f(2f(x) + 2)]^2$. Then $g'(0)=$


( A ) -4
( B ) 4
( C ) 0
( D ) -2

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