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Questions  >>  CBSE XII  >>  Math  >>  Integrals
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Choose the correct answer in $\Large \int \normalsize \frac{10x^9+10^xlog_{e^{10}}dx}{x^{10}+{10}^x}$ equals

$\begin{array}{1 1} (A)\;{10}^x-x^{10}+C \\ (B)\;{10}^x+x^{10}+C \\ (C)\;({10}^x-x^{10})^{-1}+C \\ (D)\;log({10}^x+x^{10})+C\end{array}$

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