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Q)

If f and g are differentiable functions in $[0, 1]$ satisfying $f(0) = 2 = g(1), g(0) = 0 $ and $f(1) = 6$, then for some $c \in ]0, 1[$


( A ) $2f'(c) = g'(c)$
( B ) $f'(c) = g'(c)$
( C ) $2f'(c) = 3g'(c)$
( D ) $f'(c) = 2g'(c)$

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