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# A coin is tossed 6 times In how many ways we can get the $3^{rd}$ head in the $5^{th}$ toss?

$5^{th}$ toss is head(H).
First 4 tosses can be 2 heads (H) and 2 tails(T). and
$6^{th}$ toss can be head or tail (2 ways)
This can be got in $\large\frac{4!}{2!.2!}$$\times 2$ ways.
$=12\: ways$