# The reaction of propene with $HOCl\; (Cl_2+H_2O)$ proceeds through the intermediate :
( A ) $CH_3-CHCl-CH_2^+$
( B ) $CH_3−CH^+−CH_2−Cl$
( C ) $CH_3 - CH^+ - CH_2 - OH$
( D ) $CH_3-CH(OH) - CH_2^+$