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A wire of length 2 units is cut into two parts which are bent respectively to form a square of side $=x$ units and a circle of radius $=r$ units. If the sum of the areas of the square and the circle so formed is minimum, then :

( A ) $x = 2r$
( B ) $ 2x = (\pi + 4) r$
( C ) $(4 - \pi) x = \pi r$
( D ) $2x = r$

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