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Q)

For three events A, B and C, P(Exactly one of A or B occurs) = P(Exactly one of B or C occurs) = P(Exactly one of C or A occurs) = $\frac{1}{4}$ and P (All the three events occur simultaneously) = $\frac{1}{6}$. Then the probability that at least one of the events occurs, is :


( A ) $\frac{7}{64}$
( B ) $\frac{7}{32}$
( C ) $\frac{3}{16}$
( D ) $\frac{7}{16}$

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