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In the following reactions, $ZnO$ is respectively acting as a/an : <br> (a) $ZnO + Na_2O \to Na_2ZnO_2$ <br> (b) $ZnO + CO_2 \to ZnCO_3$

( A ) base and acid
( B ) base and base
( C ) acid and acid
( D ) acid and base

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