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Q)

The escape velocity for a body projected vertically upwards from the surface of earth is $11\; km/s$. If the body is projected at an angle of $45^{\circ}$ with the vertical, the escape velocity will be :


( A ) $11 \sqrt{2} km/s$
( B ) $22 \; km/s$
( C ) $11 / \sqrt{2} m/s$
( D ) $11 \; km/s$

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