When $CH_2 = CH - COOH$ is reduced with $LiAlH_4$, the compound obtained will be :

Question

( A ) $CH_2 = CH - CH_2OH$
( B ) $CH_3 - CH_2 - COOH$
( C ) $CH_3 - CH_2 - CH_2OH$
( D ) $CH_3-CH_2-CHO$