$\begin{array}{1 1} 4!4! \\ \frac{8!}{4!} \\ 288 \\ 5!.4! \end{array}$

- No. of ways in which $ n$ different things can be arranged in a circle = $(n-1)!$

Since a garland is in circular shape, circular permutation is used.

4 flowers are to be together.

$\therefore$ they are to be considered to be one.

Hence there are 5 different type of flowers.

They can be arranged in a circle in $4!$ ways.

But these 4 flowers that are together can be arranged among themselves in $4!$ ways.

$\therefore$ The required no. of arrangements $= 4!.4!$

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