Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
0 votes

The total no. of words that can be formed using the alphabets $a,b,c,d,e,f$ taking 3 at a time so that each word has atleast one vowel is ?

$\begin{array}{1 1} 48 \\ 72 \\ 96 \\ 120 \end{array}$

Can you answer this question?

1 Answer

0 votes
There are 4 consonants and 2 vowels.
No. of words having 3 alphabets = $^6C_3\times 3$
Out of these words $^4C_2\times 3!$ words have no vowels.
$\therefore$ No. of words which have at least one vowel
$=^6C_\times 3!-^4C_3\times 3!=3!(20-4)=96$
answered Sep 4, 2013 by rvidyagovindarajan_1

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App