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A couple is of momen $\overrightarrow{G}$ and the force forming the couple is $\overrightarrow{P}$. If $\overrightarrow{P}$ is turned through a right angle, the moment of the couple thus formed is $\overrightarrow{H}$. If instead, the forcce $\overrightarrow{P}$ is turned through an angle $\alpha$, then the moment of couple becomes :


( A ) $\overrightarrow{H} \cos \alpha + \overrightarrow{G} \sin \alpha$
( B ) $\overrightarrow{H} \sin \alpha - \overrightarrow{G} \cos \alpha$
( C ) $\overrightarrow{G} \cos \alpha + \overrightarrow{H} \sin \alpha$
( D ) $\overrightarrow{G} \sin \alpha - \overrightarrow{H} \cos \alpha$

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