Email
logo

Ask Questions, Get Answers

X
 
Answer
Comment
Share
Q)

16 different things are to be distributed among 3 persons A,B,C so that B gets 1 more than A and C get 2 more than B. In how many ways this can be done?

1 Answer

Comment
A)
Need homework help? Click here.
Need revision notes? Click here.
Let A get $x$ things, then B gets $x+1$ things and C gets $x+3$ things.
$\therefore \:x+x+1+x+3=16$
$\Rightarrow\:x=4$
$i.e.,$ A gets 4 things, B gets 5 things and C gets 7 things.
$\therefore$ The required no. of ways = $^{16}C_4\times ^{12}C_5\times ^7C_7$ ways.
$=\large\frac{16!}{4!.5!.7!}$ ways.
Help Clay6 to be free
Clay6 needs your help to survive. We have roughly 7 lakh students visiting us monthly. We want to keep our services free and improve with prompt help and advanced solutions by adding more teachers and infrastructure.

A small donation from you will help us reach that goal faster. Talk to your parents, teachers and school and spread the word about clay6. You can pay online or send a cheque.

Thanks for your support.
Continue
Please choose your payment mode to continue
Home Ask Homework Questions
...