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JEEMAIN and NEET
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Mathematics
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Class11
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Permutations and Combinations
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Q)
The no. of ways in which 20 different pearls of two colours can be set alternatively on a necklace, there being 10 pearls of each colour, is ?
$\begin{array}{1 1} 9!.10! \\ 5.(9!)^2 \\ (9!)^2 \\ 5. (10 !)^2 \end{array}$
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