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Class11
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Permutations and Combinations
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20 identical marbles of green colour and 20 identical marbles of white colour can be arranged in a row in how many ways so that no two same colour marbles are adjacent?
$\begin{array}{1 1} (20 \!)^ 2 \\ 2.(20 \!)^2 \\ 2\\ 1\end{array}$
jeemain
math
class11
ch7
permutations-and-combinations
fundamental-principle-of-counting
easy
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asked
Sep 5, 2013
by
rvidyagovindarajan_1
edited
Apr 1, 2016
by
meena.p
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1 Answer
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Fix all the white marbles in one way (since the marbles are identical.)
Then fix all the green marbles in one way in between the white ones.
or
Fix all the green ones first and then fix the white ones in between the green ones.
in 1 way
$\therefore$ The required no. of arrangements = 1+1=2 ways.
answered
Sep 5, 2013
by
rvidyagovindarajan_1
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