Email
Chat with tutor
logo

Ask Questions, Get Answers

X
 
Answer
Comment
Share
Q)

There are 7 identical black balls and 4 identical white balls. In how many ways can they be arranged in a row so that no two white balls are adjacent?

$\begin{array}{1 1} 7!4! \\ ^8P_2 \\ ^8P_4 \\ ^8 C_4 \end{array}$

1 Answer

Comment
A)
Since no conditions are there for white balls,
All the 7 black balls can be arranged in one way.
White balls are to be placed in between the black balls.
There are 8 places for white balls and 4 white balls are there.
Any 4 places are to be selected out of 8 places in $^8C_4$ ways.
$\therefore $ The required no. of arrangements = $^8C_4\times 1$
Help Clay6 to be free
Clay6 needs your help to survive. We have roughly 7 lakh students visiting us monthly. We want to keep our services free and improve with prompt help and advanced solutions by adding more teachers and infrastructure.

A small donation from you will help us reach that goal faster. Talk to your parents, teachers and school and spread the word about clay6. You can pay online or send a cheque.

Thanks for your support.
Continue
Please choose your payment mode to continue
Home Ask Homework Questions
Your payment for is successful.
Continue
Clay6 tutors use Telegram* chat app to help students with their questions and doubts.
Do you have the Telegram chat app installed?
Already installed Install now
*Telegram is a chat app like WhatsApp / Facebook Messenger / Skype.
...