$\begin{array}{1 1} (A) ^{10}C_2\times ^{10}C_2 \\ (B) ^9C_2\times ^{10}C_2 \\ (C) ^9C_2\times ^{9}C_2 \\ (D) ^{19}C_4 \end{array} $

Since no. 10 is present in each selection, only 4 boxes are to be selected.

Also since no. 10 comes in $3^{rd}$ position,

first two boxes should be numbered <10 and

next two numbers should be >10.

2 numbers are to be selected from 1,2.......9 in $^9C_2$ ways

and

2 numbers are to be selected from 11,12,......20 in $^{10}C_2$ ways.

$\therefore$ The required no. of arrangements = $^9C_2\times ^{10}C_2$

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