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Permutations and Combinations
$(100)!+1$ is divisible by?
$\begin{array}{1 1} 93 \\ 87 \\ 83 \\ none\;of\;the \;above \end{array}$
jeemain
math
class11
ch7
permutations-and-combinations
fundamental-principle-of-counting
easy
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asked
Sep 5, 2013
by
rvidyagovindarajan_1
edited
Apr 5, 2016
by
meena.p
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1 Answer
$n!+1 $ is not divisible by any of the numbers from $2\:to\:n$
answered
Sep 5, 2013
by
rvidyagovindarajan_1
edited
Dec 20, 2013
by
meenakshi.p
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