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Q)

If $^nC_3=220$, then $n=?$

$\begin{array}{1 1} 10 \\ 11 \\ 12 \\ 22 \end{array}$

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A)
Given: $\large\frac{n!}{(n-3)!.3!}$$=220$
$\Rightarrow\:n(n-1)(n-2)=1320=12\times 11\times 10$
$\Rightarrow\:n=12$
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