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An element '$\mathit{X}$' decays first by positron emission and then two $\alpha$ - particles are emitted in successive radioactive decay. If the product nucleus has mass number 227and atomic number 89 the mass number and atomic number of element '$\mathit{X}$' are:

\[\begin {array} {1 1} (a)\;(273,93) & \quad  (b)\;(235,94) \\  (c)\;(238,93) & \quad (d)\;(237,92) \end {array}\]
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(b) (235,94)
answered Nov 7, 2013 by pady_1

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