Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
Home  >>  EAMCET  >>  Physics
0 votes

The average force that is necessary to stop a hammer with $25 $ N/s momentum in 0.05 $s$ is:

\[(a)\;500\;N\qquad (b)\;125\;N \qquad(c)\;50\;N \qquad (d)\; 25\;N\]
Can you answer this question?

1 Answer

0 votes
(a) 500 N
answered Nov 7, 2013 by pady_1

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App