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The average force that is necessary to stop a hammer with $25 $ N/s momentum in 0.05 $s$ is:

\[(a)\;500\;N\qquad (b)\;125\;N \qquad(c)\;50\;N \qquad (d)\; 25\;N\]
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(a) 500 N
answered Nov 7, 2013 by pady_1

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