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Q)

If $\frac{\cos A}{\cos B} = n , \; \frac{\sin A}{\sin B} = m$, then $(m^2 - n^2) \sin^2B$ is equal to :


( A ) $1+n^2$
( B ) $1-n$
( C ) $1+n$
( D ) $1-n^2$

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